I ) If ‘m1’ persons do a work in d1 days and ‘m2’ persons do the same work in d2 days, then m1d1=m2d2
II) ‘m1’ persons can do ‘w1’ work in ‘d1’ days and ‘m2’ persons do ‘w2’ work in ‘d2’ days, then (w1 / m1d1)= (w2 / m2d2)
III) If ‘m1’ persons can do ‘w1’ work in ‘d1’ days working ‘t1’ hours a day and ‘m2’ persons can do ‘w2’ work in ‘d2’ days, working ‘t2’ hours a day. Then,
(w1 / m1 d1 t1) = (w2 / m2 d2 t2).
IV) A can do a work in ‘x’ day. B can do the same work in ‘y’ days. Then A and B together can complete the work in xy / (x+y) days.
V) If A working alone takes ‘x’ days more and B working alone takes ‘y’ days more than A and B together, then the number of days taken by A and B working together is given by √xy days.
No comments:
Post a Comment